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gomongo/common.go

52 lines
1.7 KiB

2 years ago
package gomongo
import (
"errors"
"fmt"
"go.mongodb.org/mongo-driver/bson"
"go.mongodb.org/mongo-driver/bson/bsontype"
"go.mongodb.org/mongo-driver/bson/primitive"
"go.mongodb.org/mongo-driver/x/bsonx/bsoncore"
"time"
)
// https://chowdera.com/2021/01/20210128154417121y.html
type JsonTime time.Time
const (
timeFormart = "2006-01-02 15:04:05"
)
// UnmarshalJSON 实现json反序列化从传递的字符串中解析成时间对象
func (t *JsonTime) UnmarshalJSON(data []byte) (err error) {
now, err := time.ParseInLocation(`"`+timeFormart+`"`, string(data), time.Local)
*t = JsonTime(now)
return
}
// MarshalJSON 实现json序列化将时间转换成字符串byte数组
func (t JsonTime) MarshalJSON() ([]byte, error) {
b := make([]byte, 0, len(timeFormart)+2)
b = append(b, '"')
b = time.Time(t).AppendFormat(b, timeFormart)
b = append(b, '"')
return b, nil
}
// MarshalBSONValue mongodb是存储bson格式因此需要实现序列化bsonvalue(这里不能实现MarshalBSONMarshalBSON是处理Document的)将时间转换成mongodb能识别的primitive.DateTime
func (t *JsonTime) MarshalBSONValue() (bsontype.Type, []byte, error) {
targetTime := primitive.NewDateTimeFromTime(time.Time(*t))
return bson.MarshalValue(targetTime)
}
// UnmarshalBSONValue 实现bson反序列化从mongodb中读取数据转换成time.Time格式这里用到了bsoncore中的方法读取数据转换成datetime然后再转换成time.Time
func (t *JsonTime) UnmarshalBSONValue(t2 bsontype.Type, data []byte) error {
v, _, valid := bsoncore.ReadValue(data, t2)
if valid == false {
return errors.New(fmt.Sprintf("%s, %s, %s", "读取数据失败:", t2, data))
}
*t = JsonTime(v.Time())
return nil
}